The sum of first 'n' terms of an arithmetic progression is given by the formula Sn=3n2+n, then it's 3rd term is
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7
Answer:
16
Step-by-step explanation:
Sn=3n^2+n
S1=3*1^2+1
=3*1+1
=4
S1=First term=4
S2=3*2^2+2
=3*4+2
=14
second term=S2-S1
=14-4
=10
common difference = 10-4
=6
Third term=10+6
=16
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