The sum of first n terms of an arithmetic sequence is 3n²+4n write the algebraic from of the sequence
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EXPLANATION.
GIVEN
sum of n terms of an Ap = 3n^2 + 4n
write the algebraic form of the sequence.
Let,
Tn = 3n^2 + 4n - [ 3( n - 1)^2 + 4( n - 1 )]
3n^2 + 4n - [ 3 ( n^2 + 1 - 2n ) + 4n - 4 ]
3n^2 + 4n - [ 3n^2 + 3 - 6n + 4n - 4 ]
3n^2 + 4n - 3n^2 - 3 + 6n - 4n + 4
6n + 1
Therefore,
algebraic form of an Ap = 6n + 1
More information,
Formula of n terms of an Ap
sum of n terms of an Ap
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