The sum of first n terms of an arithmetic sequence is n2+4n.(a)what is its first term?
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Step-by-step explanation:
Sn=n/2{2a+(n-1)d}
we have
Sn=6n
n/2{2a+(n-1)d} =6n
n{2a+(n-1)d} =12n
2a+(n-1)d=12
2a=12-(n-1)d
a=12-(n-1)d/2
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