Question

The sum of first 'n' terms of the series a, 3a, 5a,...

Answer 1

Answer:

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Answer 2

AP: a, 3a, 5a...

First term= a , d= (3a - a) = 2a

Sn = $\frac{n}{2}$[2a + (n-1) d]

Sn = $\frac{n}{2}$[2a + (n-1) 2a]

Sn = $\frac{n}{2}$[2a + 2an - 2a]

Sn = $\frac{n}{2} × 2an$

Sn = an²

Sum of the terms= an²