The sum of first name ap is given by sn=2n2+3nfind the 16th term of an ap
superstar007:
answer is 65
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the 1st term of ap be a, and common difference be d
sum of 1st n terms Sn= n{2a+(n-1)d}/2
so, n{2a+(n-1)d}/2= 2n^2+3
when n=1
then a= 5
when n=2
2*5+d= 8+3=11
or,d=1
so 16th term=a+(n-1)d=5+15*1=20
sum of 1st n terms Sn= n{2a+(n-1)d}/2
so, n{2a+(n-1)d}/2= 2n^2+3
when n=1
then a= 5
when n=2
2*5+d= 8+3=11
or,d=1
so 16th term=a+(n-1)d=5+15*1=20
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The answer , a16 = 65..
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