the sum of first nth term of an ap is given by sn=2n^2+n then the ap is
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if sn=2n^2+n
then n=1
s1=2×1+1=3
n=2
s2=2×4+2=10
n=3
s3=2×9+3=21
so a1=s1=3
a2=s2-s1=10-3=7
a3=s3-s2=21-10=11
so we can see that the common difference between terms is 4
so the ap would be 3,7,11,15,19....
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