the sum of first q terms of an AP is 63 q-3 q square.if its p th term is -60 find the value of p and also find the 11 th term
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Hi,
Given Sq = 63q-3q2
S1 = 63 * 1 - 3* 1*1
=60 = a1 sum of first 1 term is first term
S2 = 63 * 2 - 3* 2 *2
=114
S2 - S1 = 114 - 60
=54 = a2 Sum of first two terms - sum of first term is 2 nd term.
SO , d = 54 - 60 = - 6
Now,
ap = - 60
= a + (p-1) d = - 60
= 60 + ( p-1) -6= - 60
= p-1 = -60-60 / -6
= p = 21
Now,
a11 = a+ 10 d
=60 + 10 *-6
= 60 + -60
= 0
Given Sq = 63q-3q2
S1 = 63 * 1 - 3* 1*1
=60 = a1 sum of first 1 term is first term
S2 = 63 * 2 - 3* 2 *2
=114
S2 - S1 = 114 - 60
=54 = a2 Sum of first two terms - sum of first term is 2 nd term.
SO , d = 54 - 60 = - 6
Now,
ap = - 60
= a + (p-1) d = - 60
= 60 + ( p-1) -6= - 60
= p-1 = -60-60 / -6
= p = 21
Now,
a11 = a+ 10 d
=60 + 10 *-6
= 60 + -60
= 0
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