Question

the sum of first q terms of an AP is 63q-3q2.if its pth term is -60 find the value of p.​

Answer 1

Answer:

The value of p is 20.

Step-by-step explanation:

S(q) = 63*q - 3q²

S(p) = 63*p - 3p²

t(p) = S(p) - S(p-1)= 63*p - 63(p-1) - 3p² +3(p-1)²

t(p) = 63 - 3p²+3p²-6*p-3

=> -60 = 60-6*p

=> 120 = 6*p

=>p =20.

Answer 2

Answer:

the value of p=21

hope this is right answer