Question

The sum of first seven terms of an AP is 182. If 4th and 17th terms are in the
ratio 1:5 , find the AP..​

Answer 1

Answer:

Given that 4th term and 17th term in ratio 1:5.  

                (a+3d)/(a+16d) = 1/5  

                5a + 15d = a + 16d  

                    d = 4a  ---- (1).  

We know that sum of n terms = n/2(2a+(n-1)*d)  

                       the sum of 7 terms = 7/2(2a + 6d) = 182  

                                                       = 7(a + 3d) = 182  

                                                            (a + 3d) = 26.  

                                                            (a + 3(4a)) = 26   (from (1)  

                                                           a + 12a = 26  

                                                          a = 2

Substitute a = 2 in (1)

d = 8.

The Ap = 2,10,18,26,34....

Hope this helps!

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Answer 2

Answer:

hope so it will helpful to you