Question

The sum of first six terms of an

a.p is 0 and fourth term is 2. find the sum of its first 30 terms.

Answer 1

$s(n) = \frac{n}{2} (2a + (n - 1)d)$
$s(6) = 0$
we get
$2a + 5d = 0$
fourth term is 2

a+3d = 2

now solving 2a+5d=0
a+3d=0
we get a= -10
d= 4

s(30)= 15[2(-10)+29(4)]
= 15[-20 +116]
= 15[96]
= 1440

i hope answer is correct .

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