Question

the sum of first three consecutive terms of an increasing ap is 66 and the product of first and third term 468 than the third term is​

Answer 1

Answer:

1st term be a so,2nd term a+d and third term a+2d

d is common difference

a+a+d+a+2d=66

3a+3d=66

a+d=22

2nd term =22

so,1st term a =22-d

Now,

a×(a+2d)=468

(22-d)×(22-d+2d)=468

(22-d)×(22+d)=468

484-d×d=468

-d×d=468-484

d=4

Therefore

a=18

a+d=22

a+2d=26