Question

The sum of first three terms of a geometric progression is 13/12 and their product is -1.

(i)Find common ratio.

(ii) Find geometric progression.​

Answer 1

Answer:

find common ratio........

Answer 2

Answer:According to the Q.,

let first three terms be ar^(-1),a and ar.

So,a^3=(-1) then a=(-1)

Also sum of n terms of a g.p.

a(r^n-1)/r-1

So, (-1)(r^3-1)/r-1=13/12

=r^2-r+25/12=0

=12r^2-12r+25=0.

Now solve it to get the value of r and then find the req. G.P.

I hope it helps.☺

Step-by-step explanation: