The sum of first three terms of a Geometric Progression is 13/12 and their product is-1.
Find Geometric Progression GP.
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Let the terms of the G.P. be ra,a,ar.
It is given that
ra+a+ar=1213 and ra×a×ar=−1
⇒a(rr2+r+1)=1213 and a3=−1
⇒a=−1 and a(r2+r+1)=1213r
⇒r2+r+1=−1213r
⇒12r2+25r+12=0
⇒12r2+16r+9r+12=0⇒(3r+4)(4r+3)=0⇒r=−34 or −43
Hence,three numbers are
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