The sum of first three terms of a GP. is 13/ 12 and their product is-1. Find GP.
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let the first three terms of GP be a/b, a, ab
sum = 13/12 => a/b + a + ab = 13/12
product = -1 => a/b.a.ab = -1 => a^3 = -1 => a=-1
by substituting a value in sum of the three terms and solving we get ,b = -3/4
=> GP is 4/3, -1, 3/4
Hope this helps you :)
sum = 13/12 => a/b + a + ab = 13/12
product = -1 => a/b.a.ab = -1 => a^3 = -1 => a=-1
by substituting a value in sum of the three terms and solving we get ,b = -3/4
=> GP is 4/3, -1, 3/4
Hope this helps you :)
JacOb071:
tysm☺
you're welcome :)
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