Question

The sum of first three terms of



a.p is 33. if the product of first and third term exceed the seconds term by 29 . find the



a.p.

Answer 1

Let the three terms of the AP be a-d, a and a+d.  Their sum: a-d+a+a+d = 3a = 33 or a = 11.  (a-d)(a+d)= a+29, or  (11-d)(11+d) = 11+29 = 40, or  121 - d^2 = 40, or  d^2 = 121–40 = 81, or  d = 9 or -9.  So the AP is 2, 11 and 20, or 20, 11 and 2.

Answer 2

Refer to the above attachment