the sum of first three terms of an ap is 48 if the product of first and second term exceeds 4 times the third term by 12 find the AP
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3
Answer:
1,16,31
Step-by-step explanation:
let the AP be
a-d,a,a+d
sum of AP= 48=3a
a=16
now ATQ
(a-d)a=4(a-d)+12.
16×16-16d=4×16-4×d+12
12d=180
d=15
hence AP is 16-15,16,16+15
1,16,31
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