Question

the sum of first three terms of an ap is 48 if the product of first and second term exceeds 4 times the third term by 12 find the AP ​

Answer 1

Answer:

1,16,31

Step-by-step explanation:

let the AP be

a-d,a,a+d

sum of AP= 48=3a

a=16

now ATQ

(a-d)a=4(a-d)+12.

16×16-16d=4×16-4×d+12

12d=180

d=15

hence AP is 16-15,16,16+15

1,16,31