Question

The sum of first three terms of an AP is 48. If the product of first and second term exceeds 4 times the third term by 12. Find the AP.

Answer 1

Answer:

7 , 16 , 25

Step-by-step explanation:

let say three term are

a-d  , a  , a+d

sum = 48 = a-d + a + a+d

3a = 48

a =16

(a-d)a =  4(a+d) + 12

(16-d)*16 = 4 (16+d) + 12

256 - 16d = 64 + 4d + 12

180 = 20d

d = 9

three terms are

7 , 16 , 25

Answer 2

Refers to attachment ⚘⚘