Question

The sum of first three terms of an AP is half of the sum of next three terms . If the first term is 6 then find common difference and find AP

Answer 1

a+a+d+a+2d=1/2(a+3d+a+4d+a+5d)

3a+3d=3/2×a+6d
now putting the value of a(the first term) we have
18+3d=3/2×6+6d
18+3d=9+6d
9=3d
d=3
since a=6, the AP is 6,9,12,15,18,21............

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Answer 2

Answer:

Step-by-step explanation:

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