The sum of first three terms of an AP is half the sum of its next 3 terms. If its first term is 6, find the common difference.
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Answer:
common difference (d)=3
Step-by-step explanation:
a+a+d+a+2d=1/2(a+3d+a+4d+a+5d)
3a+3d=3/2×a+6d
now putting the value of a(the first term) we have
18+3d=3/2×6+6d
18+3d=9+6d
9=3d
d=3
since a=6, the AP is 6,9,12,15,18,21............
hope this helped if yes please mark it as brainliest
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