Question

The sum of first three terms of an AP is half the sum of its next 3 terms. If its first term is 6, find the common difference.

Answer 1

Answer:

common difference (d)=3

Step-by-step explanation:

a+a+d+a+2d=1/2(a+3d+a+4d+a+5d)

3a+3d=3/2×a+6d

now putting the value of a(the first term) we have

18+3d=3/2×6+6d

18+3d=9+6d

9=3d

d=3

since a=6, the AP is 6,9,12,15,18,21............

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