The sum of first three terms of G.P is 13/12 and their product is-1. Find G.P?
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let the three terms be a/r,a,ar
now (a/r)(a)(ar)=-1
a(cube)=-1
a=-1 now
a/r+a+ar=13/12
-1-r-r(square)=13/12(r)
-12-12r-12r(square)=13r
12r(square)+25r+12=0
12r(square)+9r+16r+12=0
3r(4r+3)+4(4r+3)=0
r=-4/3 or r=-3/4
now put the values of r and you will get your answer
now (a/r)(a)(ar)=-1
a(cube)=-1
a=-1 now
a/r+a+ar=13/12
-1-r-r(square)=13/12(r)
-12-12r-12r(square)=13r
12r(square)+25r+12=0
12r(square)+9r+16r+12=0
3r(4r+3)+4(4r+3)=0
r=-4/3 or r=-3/4
now put the values of r and you will get your answer
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