Question

the sum of first three terms of gp is 13/12and their product is -1.find the common ratio and the their terms​

Answer 1

Answer:

answer is as follow

Step-by-step explanation:

According to the Q.,

let first three terms be ar^(-1),a and ar.

So,a^3=(-1) then a=(-1)

Also sum of n terms of a g.p.

a(r^n-1)/r-1

So, (-1)(r^3-1)/r-1=13/12

=r^2-r+25/12=0

=12r^2-12r+25=0.

Now solve it to get the value of r and then find the req. G.P.

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