The sum of first twenty terms of A.P which are divisble by both 2 and 5 is
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Answer:
2100
Step-by-step explanation:
The no. of terms divisible by both 2and5 :-
10,20,30,..............
Sum of the terms:-
Sn = n/2(2a + (n-1)d)
Since there are 20 terms so n = 20, a = 10,
d = 10(20-10)
Substituting the values
Sn = 20/2(2*10 + (20-1)*10)
Sn = 10(20 + 190)
Sn = 10*210
Sn = 2100 ans
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