Question

The sum of five consecutive even numbers is 220. Find the smallest of the five numbers.​

Answer 1

Answer:

40

Step-by-step explanation:

let 1st consecutive no.be x

2nd be x+2

3rd be x+4

4th be x+6

5th be x+8

A/Q

x+(x+2)+(x+4)+(x+6)+(x+8)=220

5x+20=220

5x= 220-20

5x=200

x=40

Then, smallest no.is x=40

Answer 2

Given :-

• The Sum Of 5 Consecutive even numbers is 220.

To Find :-

• Smallest Of the five numbers.

Solution :-

Let,

• First Number = x.

• Second Number = x + 2.

• Third Number = x + 4.

• Forth Number = x + 6.

• Fifth Number = x + 8.

According To The Question,

➠ x + x + 2 + x + 4 + x + 6 + x + 8 = 220.

➠ 5x + 20 = 220.

➠ 5x = 220 – 20.

➠ 5x = 200.

➠ x = 200/5.

➠ x = 40.

As we can see that, x was the smallest number.

So,

• Smallest Number = x = 40.