Question

The sum of five consecutive even numbers is 220. Find the smallest of the five numbers.​

Answer 1

Answer:

Let the number be x. Then the next 4 number will be x+2, x+4, x+6, x+8

.°. x+x+2+x+4+x+6+x+8 = 220

5x + 20 = 220

5x = 200

x = 40

Therefore the smallest of the five consecutive numbers is 40

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Answer 2

Answer:

The smallest number is 40.

Step-by-step explanation:

Let the smallest number (even) be = x

Since these are even consecutive numbers and an even number plus 2 will give its other even consecutive number, other numbers will be = x+2, x+4, x+6, & x+8

According to the equation, the sum of all 5 even consecutive numbers is 220. So,

x+x+2+x+4+x+6+x+8=220

= x+x+x+x+x+2+4+6+8=220

= 5x+20=220

= 5x=220-20=200

= x=200/5=40

= x=40

Since we took x as the smallest number, the smallest even number among the 5 is 40.