The sum of five consecutive multiple of
two is 660, then find the largest number ?
Answers
Answer:
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Answer:
264
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Step−By−Step Explanation:
In such questions you must begin bt assuming the number be variables.
Since consecutive even numbers differ by 2, let us assume the five consecutive numbers to be as follows,
x, ( x + 2 ), ( x + 4 ), ( x + 6 ) and ( x + 8 )
According to the question,
Sum of these numbers = 660
x + ( x + 2 ) + ( x + 4 ) + ( x + 6 ) + ( x + 8 ) = 660
x + x + 2 + x + 4 + x + 6 + x + 8 = 660
5x + 20 = 660
5x = 660 - 20
5x = 640
x = 640 / 5
x = 128
Therefore,
The numbers will be 128, 130, 132, 134 and 136.
Greatest Number = 136
Smallest Number = 128
The sum of greatest and smallest number = 136 + 128
The sum of greatest and smallest number = 264
Answer:
264
Step-by-step explanation:
x+(x+2)+(x+4)+(x+6)+(x+8)=660
5x+20=660
5x=660-20
x=128
Sum of greatest and smallest no. is:
(x+8)+x=(128+8)+128=264