Question

the sum of five consecutive negative integers is 2 more than the 8 times of the largest number. then find the smallest integer​

Answer 1

Answer:

The smallest number is -8

Step-by-step explanation:

To find the smallest integer ,if the sum of five consecutive negative integers is 2 more than the 8 times of the largest number

Let the largest number is -x

so consecutive five negative numbers are

-x ,-x-1,-x-2,-x-3,-x-4

So according to the question

$- x - x - 1 - x - 2 - x - 3 - x - 4 = - 8x + 2 \\ \\ - 5x - 10 = - 8x + 2 \\ \\ - 5x + 8x = 2 + 10 \\ \\ 3x = 12 \\ \\ x = 4 \\ \\ - x = - 4$

The largest number is -4

All the numbers are -4,-5,-6,-7,-8

So, the smallest number is -8.

Hope it helps you.

Answer 2

Answer:

the smallest number is 8