Question

The sum of five consecutive numbers is 250. Find difference between squares of extremes

Answer 1

x+x+1+x+2+x+3+x+4=250

5x+10=250

5x=240

x=48

So the no. s are 48,49,50,51,52

Difference b/w squares of extremes:

52^2-48^2

=2704-2304

=400

Answer 2

hope it helps !!! pls mark my solution as the BRAINLIEST