Math, asked by maneesandhu, 1 month ago

The sum of five consecutive numbers is 500.

Use n to represent the smallest number and write an equation to work out the numbers.

What is the largest of the five numbers ?

Answers

Answered by poojadancer007delhi
3

Answer:

X + X + 1 + X + 2 + X + 3 + X + 4 = 500

5x + 10 = 500

5x = 500- 10

5x = 490

X = 490/5

X = 98

X = 98

Answered by itsRakesh
2

Answer:

102

Step-by-step explanation:

Let the numbers be n,(n+1),(n+2),(n+3),(n+4). [Notice that the difference between 2 consecutive numbers is 1, which says that they are consecutive]

Now, it's given that the sum of the numbers is 500.

=> n+(n+1)+(n+2)+(n+3)+(n+4)= 500

=> 5n +10  = 500

=> n = 98

Replacing the value of n in n,(n+1),(n+2),(n+3),(n+4) , we get the numbers as 98, 99, 100, 101, and 102

Therefore, the largest of these numbers is 102.

Hope you understood. If yeah, then plz don't forget to mark my answer as the brainliest.

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