Question

the sum of five consecutive odd integers is 645. the middle integer is.​

Answer 1

Step-by-step explanation:

let the no.be x

let the no.be xfirst consecutive integer is = x

let the no.be xfirst consecutive integer is = xsecond cconsecutive integer is =x+1

let the no.be xfirst consecutive integer is = xsecond cconsecutive integer is =x+1third consecutive integer is = x+1+1 =x+2

let the no.be xfirst consecutive integer is = xsecond cconsecutive integer is =x+1third consecutive integer is = x+1+1 =x+2fourth consecutive integer is =x+1+1+1 =x+3

let the no.be xfirst consecutive integer is = xsecond cconsecutive integer is =x+1third consecutive integer is = x+1+1 =x+2fourth consecutive integer is =x+1+1+1 =x+3fifth consecutive integer is =x+1+1+1+1 =x+4

let the no.be xfirst consecutive integer is = xsecond cconsecutive integer is =x+1third consecutive integer is = x+1+1 =x+2fourth consecutive integer is =x+1+1+1 =x+3fifth consecutive integer is =x+1+1+1+1 =x+4A.T.Q

let the no.be xfirst consecutive integer is = xsecond cconsecutive integer is =x+1third consecutive integer is = x+1+1 =x+2fourth consecutive integer is =x+1+1+1 =x+3fifth consecutive integer is =x+1+1+1+1 =x+4A.T.Q x+x+1+x+2+x+3+x+4 = 645

let the no.be xfirst consecutive integer is = xsecond cconsecutive integer is =x+1third consecutive integer is = x+1+1 =x+2fourth consecutive integer is =x+1+1+1 =x+3fifth consecutive integer is =x+1+1+1+1 =x+4A.T.Q x+x+1+x+2+x+3+x+4 = 645 4x+10 = 645

let the no.be xfirst consecutive integer is = xsecond cconsecutive integer is =x+1third consecutive integer is = x+1+1 =x+2fourth consecutive integer is =x+1+1+1 =x+3fifth consecutive integer is =x+1+1+1+1 =x+4A.T.Q x+x+1+x+2+x+3+x+4 = 645 4x+10 = 645 4x = 645-10

let the no.be xfirst consecutive integer is = xsecond cconsecutive integer is =x+1third consecutive integer is = x+1+1 =x+2fourth consecutive integer is =x+1+1+1 =x+3fifth consecutive integer is =x+1+1+1+1 =x+4A.T.Q x+x+1+x+2+x+3+x+4 = 645 4x+10 = 645 4x = 645-10 4x = 635

let the no.be xfirst consecutive integer is = xsecond cconsecutive integer is =x+1third consecutive integer is = x+1+1 =x+2fourth consecutive integer is =x+1+1+1 =x+3fifth consecutive integer is =x+1+1+1+1 =x+4A.T.Q x+x+1+x+2+x+3+x+4 = 645 4x+10 = 645 4x = 645-10 4x = 635 X = 635÷4

let the no.be xfirst consecutive integer is = xsecond cconsecutive integer is =x+1third consecutive integer is = x+1+1 =x+2fourth consecutive integer is =x+1+1+1 =x+3fifth consecutive integer is =x+1+1+1+1 =x+4A.T.Q x+x+1+x+2+x+3+x+4 = 645 4x+10 = 645 4x = 645-10 4x = 635 X = 635÷4 X = 158.7