the sum of five consecutive whole numbers list 2015 what is the smallest number among the five numbers is
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let the nos. be x ,x+1x+2,x+3,x+4
according to question
x+x+1+x+2+x+3+x+4=2015
5x+10=2015
5x=2005
x=2005/5=401
thus the smallest no. is 401
and the other four nos. are 402,403,404 &405
according to question
x+x+1+x+2+x+3+x+4=2015
5x+10=2015
5x=2005
x=2005/5=401
thus the smallest no. is 401
and the other four nos. are 402,403,404 &405
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