Question

the sum of five times a number and four times another number is 47 and the sum of four times ofnthe first number and five times of the second is 43. find the numbers
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Answer 1

Answer:

let the numbers be x and y

5x+4y=47. (1)

4x+5y=43. (2)

on adding the two equation we get

9x+9y=90

x+y=10. (3)

on subtracting the equation 1&2

x-y=4. (4)

on adding equation 3&4 we get

2x=14

x=7

so,x+y=10

7+y=10

y=3

The answer is x=7 and y=3

Answer 2

Answer:

Let the numbers be x and y

5x + 4y = 47.......(1)

4x + 5y = 43.......(2)

On adding two equation. we get,

9x + 9y = 90

x + y = 10.........(3)

On subtracting the equation 1&2. we get,

x - y = 4.......(4)

On adding equation3&4. we get,

2x = 14

x = 7

Substituting x value in (3)

7 + y = 10

y = 10 - 7

y = 3.