The sum of four consective odd number is 128 find the number
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Answered by
0
Let four consecutive numbers are
2x + 1
2x + 3
2x + 5
2x + 7
=================
According to the question,
2x + 1 + 2x + 3 + 2x + 5 + 2x + 7 = 128
8x + 16 = 128
8x = 128 - 16
8x = 112
x = 1114/8
x = 14
==================
Numbers are :
• 2(14) + 1 = 28+1=29
• 28 + 3=31
• 28 + 5=33
• 28+7=35
I hope this will help you
(-:
2x + 1
2x + 3
2x + 5
2x + 7
=================
According to the question,
2x + 1 + 2x + 3 + 2x + 5 + 2x + 7 = 128
8x + 16 = 128
8x = 128 - 16
8x = 112
x = 1114/8
x = 14
==================
Numbers are :
• 2(14) + 1 = 28+1=29
• 28 + 3=31
• 28 + 5=33
• 28+7=35
I hope this will help you
(-:
Answered by
0
Heya !!!
Let first consecutive odd number be X +1
Other Three will be = ( X +3) ( X +5) ( X +7)
According to question,
Sum or these numbers = 128
X + 1 + X + 3 + X + 5 + X + 7 = 128
4X + 16 = 128
4X = 128-16
4X = 112
X = 112/4
X = 28
HENCE,
First Number = X +1 = 28 +1 = 29
Second Number = X +3 = 28+3 = 31
Third Number = X +5= 28 +5 = 33
And,
Fourth Number = X +7 = 28+7 = 35.
HOPE IT WILL HELP YOU.... ;-)
Let first consecutive odd number be X +1
Other Three will be = ( X +3) ( X +5) ( X +7)
According to question,
Sum or these numbers = 128
X + 1 + X + 3 + X + 5 + X + 7 = 128
4X + 16 = 128
4X = 128-16
4X = 112
X = 112/4
X = 28
HENCE,
First Number = X +1 = 28 +1 = 29
Second Number = X +3 = 28+3 = 31
Third Number = X +5= 28 +5 = 33
And,
Fourth Number = X +7 = 28+7 = 35.
HOPE IT WILL HELP YOU.... ;-)
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