Question

The sum of four consecutive even integers is 84. what are the integers? leave steps please

Answer 1

hey there
let the no be x
second no be x +2
third no be x +4
fourth no be x +6( we are taking consecutive even integers)
now x +x+2+x+4+x+6 = 84
4x + 12 = 84
4x = 84 -12
4x = 72
x = 72/4
x = 18
hence the numbers are 18 , x +2 = 18 +2 = 20 , x +4 = 18 + 4 = 22 , x +6 = 18 +6 = 24
^_^

Answer 2

HERE IS YOURS SOLUTION;

◆ Let the consecutive even integers be X , X + 2 , X + 4 , X + 6 --------1)

According to the question;

X + X + 2 + X + 4 + X + 6 = 84

=> 4X + 12 =84

=> 4X = 84 - 12

=> 4X = 72

=> X = 72 ÷ 4

=> X = 18.

Now, by putting the values in equation 1), We get;


◆ So the Integers are 18 , 20 , 22 , 24 ◆


HOPE IT HELPS