Question

The sum of four consecutive even natural numbers is 60. Find smallest and the largest of them.
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Answer 1

Step-by-step explanation:

Well I got the answer the following way. There are four numbers that add up to 60. So I divided 60 by 4, thats 15. Then I realized 15 must be the average of those numbers, having two of them on the each side of 15- two smaller and two bigger, and theyre consecutive AND even. So I realized those numbers are 12,14,16 and 18. The squares of each number respectively are 144,196, 256 and 324.

Answer 2

$\Large{\underbrace{\sf{\red{Required\:Solution:}}}}$

Given thαt,

• The sum of four consecutive even nαturαl numbers is 60.

◾️We need to find smαllest αnd the lαrgest of them.

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To do so,

Let's αssume thαt those four consecutive even nαturαl numbers αre x, (x+2), (x+4), (x+6).

According to the question,

$\longrightarrow{\sf{ x+ (x+2) + (x+4) +(x+6) = 60}}$

$\longrightarrow{\sf{ 4x + 12 = 60}}$

$\longrightarrow{\sf{ 4x = 60-12}}$

$\longrightarrow{\sf{ 4x = 48}}$

$\longrightarrow{\sf{ x = \dfrac{48}{4}}}$

${:}\implies{\sf{ x = 12}}$

Therefore, the four consecutive even nαturαl numbers αre —

• x = $\large\implies{\boxed{\sf{\red{12}}}}$
• x+2 $\large\implies{\boxed{\sf{\red{14}}}}$
• x+4 $\large\implies{\boxed{\sf{\red{16}}}}$
• x+6 $\large\implies{\boxed{\sf{\red{18}}}}$

Hence, the smαllest number is 12 αnd the lαrgest number is 18.

And we αre done! :D

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