Question

the sum of four consecutive even number is 23 more than the sum of three consecutive odd number. the difference between the lowest even and highest odd number is 3. find the sum of four consecutive even number?

Answer 1

sum of 4 con. even no. =4a+12

sum of 3 con. odd no. = 3b+6

given that 4a+12 = 3b+6+23 (1)

and (b+4)-a= 3

ie. a-b = -1 (2)

from (1) & (2)

4a-3b = 17 (3)

a-b = -1 (4)

from (3) & (4) by elimination of a and b we get :-

a=14 & b= 13 as the smallest even and odd nos. here.

Answer 2

Answer:

-4

Step-by-step explanation:

(x+x+2+x+4+x+6)= four consecutive even number sum

=>4x+12.

(y+y+2+y+4)= three consecutive odd number sum

=>3y+6.

from first line of question

4x+12=3y+6+23

4x+12=3y+29

4x=3y+17-----(i)

from second line of question

x-(y+4)=3

x-y-4=3

y=x-7-----(ii)

substituting (ii) in (i),

4x=3(x-7)+17

we get,

x=-4.

now putting the value of x in sum of four even consecutive number, we get,

4x+12

=>4(-4)+12

=-4(ANS)