Question

the sum of four consecutive integer is 178.what are the integers?(is there a quick solution to this problem)

Answer 1

Yes. Here's the answer:

Sum of 4 consecutive integers= 4x+ 6
(x, x+1, x+2, x+3)
given,
4x+6= 178
=> 4x= 172
=> x= 43.
The integers are 43, 44, 45, 46 that add up to 178.

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In search of formula? Here it is:

¶¶ Sum of n consecutive no.s
= nx + [(n-1)!]

Replacing n by 4 gives 4x+6.

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More Directly,
Smallest Integer
= (1/n)[SUM - (n-1)!]

Here, SUM is Sum of 'n's consecutive no.s

Here
= (1/4)[ 178 - (3!) ]
= 172/4
= 43

(°•° 3!= 3×2×1 = 6)

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:)
hope it helps.

Answer 2

Hi.. this is the solution to your problem
Let x=first integer
Your equation on finding 4 consecutive integer will be..
x + (x+1) + (x+2) + (x+3) = 178
4x + 6 = 178
4x = 172
x = 43

Therefore the integers are 43, 44, 45 and 46.
Mark brainliest or thanks please :D