Question

The sum of four consecutive integers is 102. find the product of the extremes:

Answer 1

HELLO DEAR,

Let the fist consecutive number be x, the second one must be x+1 and the third would be x+2 and fourth be (x + 3).

Therefore:

x + (x+1) + (x+2) + (x + 3) = 102

⇒4x + 6 = 102

⇒4x = 102 - 6

⇒4x = 96

⇒x = 24

product of extremes = (x)(x + 3)

⇒(24)(24 + 3)

⇒(24)(27)

⇒648

I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

Let Integers are : x, (x + 1), (x + 2), (x + 3)



According to the question,



$x + (x + 1) + (x + 2) + (x + 3) = 102 \\ \\ x + x + 1 + x + 2 + x + 3 = 102 \\ \\ 4x + 6 = 102 \\ \\ 4x = 102 - 6 \\ \\ 4x = 96 \\ \\ x = \frac{96}{4} \\ \\ x = 24$


Numbers are :

x = 24
x + 1 = 24 + 1 = 25
x + 2 = 24 + 2 = 26
x + 3 = 24 + 3 = 27


Product of extremes : x (x + 3)

=> (24)(27)

=> 648



I hope this will help you


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