The sum of four consecutive multiple 6 is 132??
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Let the sum of consecutive multiplies of 6 = x,x + 6, x + 12, x + 18.
Given that sum of four consecutive multiplies of 6 is 132.
⇒ x + x + 6 + x + 12 + x + 18 = 132
⇒ 4x + 36 = 132
⇒ 4x = 132 - 36
⇒ 4x = 96
⇒ x = 24.
Then,
⇒ x + 6 = 30
⇒ x + 12 = 36
⇒ x + 18 = 42.
Therefore, the numbers are 24,30,36,42.
Hope this helps!
Answered by
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Let the terms be x, x+1 , x+2 , x+3
According to question;
Sum of terms multiple of 6 = 132
6x + 6(x+1) + 6(x+2) + 6(x+3) = 132
6(x + x + 1 + x + 2 + x +3) = 132
4x + 6 = 132/6
4x + 6 = 22
4x = 16
x = 4
Hence, Those terms are 4 , 5 , 6 and 8
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