Math, asked by ankit24yadv, 1 year ago

The sum of four consecutive multiple 6 is 132??
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Answered by siddhartharao77
6

Let the sum of consecutive multiplies of 6 = x,x + 6, x + 12, x + 18.

Given that sum of four consecutive multiplies of 6 is 132.

⇒ x + x + 6 + x + 12 + x + 18 = 132

⇒ 4x + 36 = 132

⇒ 4x = 132 - 36

⇒ 4x = 96

⇒ x = 24.


Then,

⇒ x + 6 = 30

⇒ x + 12 = 36

⇒ x + 18 = 42.


Therefore, the numbers are 24,30,36,42.


Hope this helps!

Answered by Shubhendu8898
7

Let the terms  be x,  x+1 , x+2 , x+3

According to question;

Sum of  terms multiple of 6  = 132

6x + 6(x+1) + 6(x+2) + 6(x+3) = 132

6(x +  x + 1  + x + 2 + x +3) = 132

4x + 6  = 132/6

4x + 6 = 22

4x = 16

x = 4


Hence, Those terms are  4 , 5 , 6 and  8



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