Question

The sum of four consecutive multiples of 4 is 72 . Find the numbers. Note: Write the numbers in the increasing order. Any multiple of 3 is of the form 3n.

Answer 1

Answer:

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so here we go

Step-by-step explanation:

let the four consecutive multiples of four be 4n,4n+4,4n+8 and 4n+12

according to given condition

4n+4n+4+4n+8+4n+12=72

ie 16n+24=72

ie 16n=48

ie n=3

substitute in missing values

we get

4n=4×3

=12

4n+4

=(4×3)+4

=16

4n+8

=(4×3)+8

=11+8

=20

and 4n+12

=(4×3)+11

=12+12

=24

so hence here required four consecutive multiples of 4 are 12,16,20 and 24

24