The sum of four consecutive multiples of 5 is 330. Find the numbers.
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Step-by-step explanation:
Let the first no. be x
Then the second and third nos. will be x+5 and x+10 respectively
AC/Q
x+x+5+x+10=330
3x+15=330
3x=330-15
3x=315
x=315/3=105
The multiples are 105, 110 and 115.
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