Question

The sum of four consecutive multiples of 7 is 126.Find these multiples.​

Answer 1

Answer:

Let the four consecutive multiples of 7 be x, x+7,x+14 and x+21

x+x+7+x+14+x+21=126

=>4x+42=126

=>4x=126-42

=>4x=84

=>x=84/4

=>x=21

Therefore,the numbers are 21,28,35 and 42

Answer 2

Three consecutive multiples of 7

$\large\rm \: x, \: x + 7, \: x + 14, \: x + 21$

$\large\rm \: x + \: x + 7 + \: x + 14 + \: x + 21 = 126$

$\large\rm \: 4x + 42 = 126$

$\large\rm \: 4x = 126 - 42$

$\large\rm \: 4x = 84$

$\large\rm \: x = \frac{84}{4}$

$\large\rm \: x = 21$

• First consecutive multiple = 21
• Second consecutive multiple = 28
• Third consecutive multiple = 35
• Forth consecutive multiple = 42

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@Antrasingh72