Question

The sum of four consecutive multiples of 7
is 322 . Find the smallest multiple
involved​

Answer 1

Answer:

184

Step-by-step explanation:

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Answer 2

Answer:

(7n) +(7n+7)+(7n+14)+(7n+21)=322

28n+42=322

28n= 322-42

n= 280/28

hence, n= 10

n= 7×10 = 70

n+1= 7(10+1)= 77

n+2= 7(10+2) = 84

n+3= 7(10+3) = 91

➺ CHECK OUT:-

CHECK OUT:-70+77+84+91 = 322

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