Question

The sum of four consecutive multiples of 7 is 70 find the numbers

Answer 1

Hey!

________________________

• Let 4 consecutive numbers be- n, n+1, n+2, n+3

• As they are multiples of 7,

Consecutive multiples are - 7n, 7(n+1) , 7(n+2) , 7 (n+3)

• Sum of these 4 consecutive multiples = 70

=> 7n+7(n+1)+7(n+2)+7(n+3)= 70

=> 7n+7n+7+7n+14+7n+21=70

=> 28n+42=70

=> 28n= 70-42

=> 28n=28

n= 1

Now,

One number = 7×1=7

Second number = 7(1+1) , 7×2=14

Third number= 7(1+2) , 7×3=21

Fourth number = 7(1+3), 7×4=28

CHECK -:

7+14+21+28=70 , as told in the Question.

________________________

Hope it helps...!!!

Have a great day ahead !

: )

Answer 2

Answer:

.Please find the attachments

Step-by-step explanation:

hope it's help you