the sum of four consecutive multiples of 7 is 70 . find these multiples
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Let the first consecutive multiple of 7 be x.
then,2nd multiple = x + 7
3rd multiple = x + 14
& 4th multiple = x + 21
according to your question,
x + x + 7 + x + 14 + x + 21 = 70
or 4x + 42 = 70
or 4x = 70 - 42
or 4x = 28
or x = 28
4
or x = 7.
Hence the 1st multiple = x = 7
2nd multiple = x + 7 = 7 + 7 = 14
3rd multiple = x + 14 = 7 + 14 = 21
4th multiple = x + 21 = 7 + 21 = 28 .
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