Question

The sum of four consecutive multiples of 7 is 70. Find these multiples.

Answer 1

Heya bro..

Let’s first understand what the s consecutivety.

Consecutive no. Means—->> no. Without any integral gaps for example.

Consecutive multiples of 3 are—-> 3..6..9...12..etc

Therefore similarly it’s ask about the sum of consecutive 4 multiples of 7.


So here we go now...



Let the first no be x.—1
S cons will be automatically 7+x—-2

3rd willbe x+14—3
And 4th is x+21—4






There fire re let’s make it all equations.




So now..let’s add all of them according to the question.


It will be


X+x+7+x+14 x+21=70—-given


So now..


Adding all—-


4x+42=70

So x =7.

Thereofore., other all no. Are


7,14,21,28..these are all the terms..


Hope it helps uh.
Else ask any doubt
Thanks..

Answer 2

Hey!

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Let 4 consecutive numbers be- n, n+1, n+2, n+3
As they are multiples of 7,

Consecutive multiples are - 7n, 7(n+1) , 7(n+2) , 7 (n+3)

Sum of these 4 consecutive multiples = 70

7n+7(n+1)+7(n+2)+7(n+3)= 70
7n+7n+7+7n+14+7n+21=70
28n+42=70
28n= 70-42
28n=28
n= 1

Now,

One number = 7×1=7
Second number = 7(1+1) , 7×2=14
Third number= 7(1+2) , 7×3=21
Fourth number = 7(1+3), 7×4=28

CHECK -:

7+14+21+28=70 , as told in the Question.


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Hope it helps...!!!