Question

The sum of four consecutive multiples of 7 is 70. Find these multiples.​

Answer 1

Answer :-

• The four consecutive multiples of 7 whose sum is 70 are 7, 14, 21 and 28.

To find :-

• The four consecutive multiples of 7 whose sum is 70.

Solution :-

• Let the first multiple of 7 be "x".

Then :-

• The next three consecutive multiples of 7 will be "x + 7", "x + 14" and "x + 21".

It is given that :-

• The sum of these four consecutive multiples of 7 is 70.

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Therefore,

$\hookrightarrow\sf x + x+ 7 + x + 14 + x + 21 = 70$

$\hookrightarrow\sf4x + 42 = 70$

$\hookrightarrow\sf4x = 70 - 42$

$\hookrightarrow\sf4x = 28$

$\hookrightarrow\sf x = \dfrac{28}{4}$

$\hookrightarrow \underline{\boxed{\sf x = 7}}$

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Hence, the multiples are :-

$\bf x = 7.$

$\bf x + 7 = 7 + 7 = 14.$

$\bf x + 14 = 7 + 14 = 21.$

$\bf x + 21 = 7 + 21 = 28.$