Question

The sum of four consecutive multiples of 8 is 816 . Find the highest among the four

Answer 1

Answer:

Let 1st number = x.

So, another 3 numbers = ( x + 4 ) , ( x + 8 ) , ( x + 12 ).

A/Q,

⇒ x + x + 4 + x + 8 + x + 12 = 120

⇒ 4x + 24 = 120

⇒ 4x = 120 - 24

⇒ 4x = 96

⇒ x = 96 ÷ 4

∴ x = 24.

Hence, numbers = x = 24

⇒ x + 4 = 24 + 4 = 28

⇒ x + 8 = 24 + 8 = 32

⇒ x + 12 = 24 + 12 = 36

Numbers = 24 , 28 , 32 and 36

Answer 2

Answer:

16x+24x+32x+40x=816

=112x=816

x=816/112

X=6.689