Question

the sum of four consecutive multiplies of 7 is 70 find these multiples please jaldi do answer ​

Answer 1

Answer:

7,14,21,28

Step-by-step explanation:

The four consecutive multiples are 7,14,21,28

Answer 2

Let 4 consecutive numbers be - n, n+1, n+2, n+3

Consecutive multiples are - 7n, 7(n+1) , 7(n+2) , 7 (n+3)

Sum of these 4 consecutive multiples = 70

7n + 7(n+1) + 7(n+2) + 7(n+3) = 70

7n + 7n + 7 + 7n + 14 + 7n + 21 = 70

28n + 42 = 70

28n = 70 - 42

28n = 28

n = 1

Now,

One number = 7 × 1 = 7

Second number = 7(1+1) , 7 × 2 = 14

Third number= 7(1+2) , 7 × 3 = 21

Fourth number = 7(1+3), 7 × 4 = 28.

hope it helps you mate.

please thank and Mark my answer as brainliest.

@ ANUSHA ❤✌