Question

The sum of four consecutive number in an AP is 32 and the ratio of the product of first and last tetm to the product of two middle term is 4:15 find the number​

Answer 1

Answer:

Let the consecutive no.s be a-d,a,a+d,a+2d

Sum=a+a-d+a+d+a+2d=>4a+2d=32=>2a+d=16

=>a=(16-d)/2

(a-d)(a+2d)/a(a+d) =4/15

15(a^2+2ad-ad-2d^2)=4(a^2+ad)

15a^2+15ad-30d^2=4a^2+4ad

11a^2+11ad-30d^2=0

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