Question

The sum of four consecutive number is 56.find the number

Answer 1

Answer :-

• The numbers are 11, 13, 15 and 17 respectively.

Correction :-

• The sum of four odd consecutive numbers is 56.

To Find :-

• The numbers.

Solution :-

Let

• First consecutive odd number be x
• Second consecutive odd number be x + 2
• Third consecutive odd number be x + 4
• Fourth consecutive number be x + 6

→ Sum of these numbers is 56

According to question :-

x + (x + 2) + (x + 4) + (x + 6) = 56

⇒ x + x + 2 + x + 4 + x + 6 = 56

⇒ x + x + x + x + 2 + 4 + 6 = 56

⇒ 4x + 12 = 56

⇒ 4x = 56 - 12

⇒ 4x = 44

⇒ x = 44/4

⇒ x = 11

Hence, the numbers are

• x = 11
• x + 2 = 11 + 2 = 13
• x + 4 = 11 + 4 = 15
• x + 6 = 11 + 6 = 17

Answer 2

$\huge{\underline{ \mathtt{\red{❥A} \green{n}\mathtt\blue{s} \purple{w} \mathtt \orange{e}\pink{r}}}}\:$

Let $x$be the first number

$x+2$ be the second

$x+4$ be the third

$x+6$ be the fourth

$⟾ (x)+(x+2)+(x+4)+(x+6) = 56$

$⟾{x+x+x+x = 56-2-4-6}$

$⟾{4x = 44 }$

$⟾\sf{ \cancel\dfrac{44}{4}$

$\rm{⟾x=11}$

$⟾x+2=11+2= 13$

$⟾x+4=11+4= 15$

$⟾x+6=11+6=17$

$\sf\underline\green{Verification:-}$

$11+13+15+17= 56$

$56 = 56$